Roger the Mole. S = -2 + 6 . to ? The Oxidation states in in SO3(g) are: Sulfur (+6) & Oxygen (-2), b/c SO3(g) has no charge. Sum of charges in this case, for these polyatomic ions, equals the charge on the ion. S + - 6 = -2 . Mg + Cl2 mc005-1.jpg Mg2+ + 2Clmc005-2.jpg. Add . 4 years ago. c. Oxidation State of Sulfur + (3 Oxidation state of Oxygen) = -2 Oxidation state of sulfur + (3 (-2 view the full answer Previous question Next question Favorite Answer. What is the oxidation number for S in the compound SO3? S is reduced and its oxidation number goes from 6+ … However in SO3^2- (aq) the Oxidation states are: Sulfur (+4) & Oxygen (-2). 2 Answers. d. Which identifies an oxidation-reduction reaction? Relevance. The alkali metals (group I) always have an oxidation number … ... Why? The oxidation number (ON) of an element details the number of electrons lost or gained by the element in order to achieve its current state. That would be the oxidation number. Fluorine in compounds is always assigned an oxidation number of -1. The sum of the oxidation numbers of all of the atoms in a neutral compound is zero. x= +4 Answer: oxidation number of S in SO3-2 is +4. (Recall that O has an oxidation number of -2.) The oxidation number for SULFUR is +4, and the oxidation number for oxygen is -2. hydrogen. Answer (g) :- Fe2(SO3)3 species contain SO3(2-) ion. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion. + indicates +1 charge, sum of charges of compounds always equals zero. The given compound is, Let the oxidation state of S be, 'x' Hence, the oxidation state of S is, (+4) (Recall that O has an oxidation number of -2.) Since the zinc ion's charge is +2, so is its oxidation number (rule 2). For HSO3- it is the negative sign, indicating a -1 charge for the bisulfite ion. It can be determined using the following rules: 1. Electrons are transferred. The oxidation number of a monatomic ion equals the charge of the ion. Oxygen has an oxidation number of 2-. The sulphite anion is SO3^2- Using '-2' for oxygen as the yardstick . Hydrogen has an oxidation number of 1+. Answer Save. and its oxidation number goes from ? c. Given the reaction below, which is the oxidized substance? so, x+3(-2)= -2. x-6=-2. The easiest way is to remember certain common numbers: O (in most cases): -II, H: +I For oxidation numbers we use Roman numerals! Lv 7. What is the oxidation number for S in the compound SO3? PLEASE HELp In the redox conversion of SO3 to SO−, S is ? Then there are 3 oxygens hence 3 x -2 = -6 . The oxidation number of a Group 17 element in a binary compound is -1. Because the sulfite ion (SO3) has a -2 charge (and you'd have to consult a list of polyatomic ions to know that) and the zinc ion MUST be +2 in order to balance that out. Don't get the two confused, they may both be written with out the charge, but if SO3 is (aq) it has a charge of -2. The oxidation number of a free element is always 0. Explanation: let oxidation number of S be x. oxidation number of O is -2 . To answer this question, let's first look at the atoms in the compounds for which we know the oxidation number. S = 4 The oxid'n number of sulphur. Since the anion has an oerall charge of '-2 ' , then we create a sum . So, in SO3, in order to create a net neutral, or zero charge, the S must have an oxidation number 6+ to cancel out the 3*(-2)= -6 of the oxygen in the compound. Which best identifies why the rusting of an iron nail in the presence of water and oxygen is an oxidation-reduction reaction? Commonly, sulfur (s) forms 2- oxidation state, but in bisulfite it forms 4+. Rules for assigning oxidation numbers. Consider the following reaction.